(1/9)^4x+8=27^5x-8

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Solution for (1/9)^4x+8=27^5x-8 equation: 



(1/9)^4x+8=27^5x-8

We move all terms to the left:

(1/9)^4x+8-(27^5x-8)=0



Domain of the equation: 9)^4x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/9)^4x-(27^5x-8)+8=0

We get rid of parentheses

(+1/9)^4x-27^5x+8+8=0

We multiply all the terms by the denominator


(+1-27^5x*9)^4x+8*9)^4x+8*9)^4x=0

Wy multiply elements

648x^2+(+1-27^5x*9)^4x=0

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